the photoelectric thresold wavelength for potassiun having work function of 2eV is
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As we have E = hc/
And E = 2eV
⇒ = hc/E = (6.6 x 10-34 x 3 x 108)/2 x (1.6 x 10-19) = 6.18 x 10-7 m ≈ 620 nm
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ANSWER :- 620 nm
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