Question

the photoelectric work function of a metal is 5 eV .calculate the threshold frequency and threshold wavelength .h=6.6×10-³⁴ js , C= 3×10⁸ m/a ​

Answer 1

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Answer 2

Given:

W₀=5 eV,h=6.6×10-³⁴ js , C= 3×10⁸ m/a ​

Explanation:

• The threshold frequency of light is the frequency at which an electron may be dislodged from an atom.This energy is used up completely in the process. As a result, at the threshold frequency, the electron receives no kinetic energy and is not liberated from the atom.

W₀=he/λ₀

λ₀=he/W₀

λ₀$=\frac{6.6*10^{-34}*3*10^{8} }{5*1.6*10^{-19} }$

$=\frac{19.8*10^{-26} }{8*10^{-19} }$

$=2.475*10^{-7}$

λ₀$=2475$ A⁰

• The maximum wavelength that incoming light must have in order for the photoelectric effect to occur is known as the threshold wavelength. The minimal energy required to remove an electron from a solid to a location in vacuum just outside the solid's surface is specified as the Work function.

f₀=c/λ₀

$=\frac{3*10^{8} }{2.475*10^{-7} }$

f₀$=1.2*10^{-15}$