Question

The photograph of a house occupies an area of 1.75 cm² on a 35mm slide. The slide is projected onto a screen and the area of the house on the screen is 1.55 m². What is the linear magnification of the projector screen arrangement?

Answer 1

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➧ Area of the house on the slide
➾ 1.75 cm²

➧ Area of the image of the house formed on the screen
➾ 1.55 m²

➾ 1 m = 100 cm
➾ 10² cm

➧ Area of the image of the house formed on the screen

➾ 1.55 m² = 1.55 × (10² cm)²
➾ 1.55 × 10^4 cm²
➧ Arial magnification

➾ area of image / area of slide

➾ 1.55 × 10^4 cm² / 1.75 cm²
➾ 0.8857 × 10^4  

➧ Linear magnifications

➾ √(Arial magnification )

➾ √(0.8857 × 10^4)

➾ 0.9411 × 10²

➾ 94.11 ...✔

_________
Thanks...✊

Answer 2

Read first statement carefully, it is clearly mentioned that "photograph of house".... photograph is the object. and then the next statement states that... the slide containing photograph is "projected" on to screen..... which means that the image of given photograph is formed on the screen.

Accordingly, take the values and calculate.

Exact calculation gives 94.11

Thanks....

Hope, it helps u...