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(i)area of ∆ abf = 1/2×b×h
5×6/2
=15cm
(ii)area of trapezium bcfh = 1/2 × h × ( b1 + b2)
=5×15/2
=75/2
=37.5cm
(iii) area of ∆ chd = 5 × 9 /2
= 45/2
= 22.5cm
(iv)area of ∆ age. = 8×3/2
= 24 / 2
= 12 cm
(v)area of ∆ dge = 7×3/2
= 21 / 2
= 10.5 cm
area of Pentagon =(15 + 37.5 + 22.5 + 12 + 10.5)cm2
= 97.5 cm2
5×6/2
=15cm
(ii)area of trapezium bcfh = 1/2 × h × ( b1 + b2)
=5×15/2
=75/2
=37.5cm
(iii) area of ∆ chd = 5 × 9 /2
= 45/2
= 22.5cm
(iv)area of ∆ age. = 8×3/2
= 24 / 2
= 12 cm
(v)area of ∆ dge = 7×3/2
= 21 / 2
= 10.5 cm
area of Pentagon =(15 + 37.5 + 22.5 + 12 + 10.5)cm2
= 97.5 cm2
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