The picture below shows a trapezium divided into four parts by the diagonals.The area of blue triangle is 4 sq.cm and the area of the green triangle is 9 sq.cm. what is the total area of the trapeziumm?
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Area of trapezium ABCD = Area of ∆ ABD + Area of ∆ CBD
= 1/2 × a × h + 1/2 × b × h
= 1/2 × h × (a + b)
= 1/2 (sum of parallel sides) × (perpendicular distance between them)
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