Question

the pieces of timber 42m 49 metre 63 M long have to be divided into planks of the same language what is the greater possible length of each blanks

Answer 1

first of all find the HCF of given length
so, HCF = 7
each pieces of timber divided by 7
so, 1st timber = 42/7= 6m
in 2nd timber = 49/7= 7m
and 3rd timber = 63/7= 9m
hence the greater possible length of each blanks is 6m, 7m, and 9m