Question

The pillar of a temple are cylindrically shaped.each pillar has a circular base. Of radius 2ocm and height 10m how much concrete mixture would be required to build 14 such pillar

Answer 1

Step-by-step explanation:

Hight of cylinder =h=10 m

Radius =r=20 cm

=20 1 upon 100m= 2upon 10m

Volume of concrete in 1 cylindrical pillar = पाई

r स्क्वायर h

=22 upon 7 multiply 2 upon 10 multiply 2upon 10 multiply 10m=88upon 70m3

Volumer of concrete in cylindrical pillar=88uponS

70 m3

So'volume of concrete in 14 cylindrical pillars 14 multiply 88upon 70 m3 17.6m3

Answer 2

Step-by-step explanation:

★ Concept ::

Here the concept of Volume of Cylinder has been used. We see that the pillars are Cylindrical in shape and each pillar is made up of concrete mixture. We have to find the amount of concrete mixture. We are given the dimensions of the pillar. If we find the volume of the pillar, then we will get volume of concrete used in one pillar and thus we can find for 14 such pillars.

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★ Formula Used :-

\;\boxed{\sf{\pink{Volume\;of\;Cylinder\;=\;\bf{\pi r^{2}h}}}}

VolumeofCylinder=πr

2

h

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★ Solution :-

» Radius of each pillar = r = 20 cm

» Height of the pillar = H = 10 cm

» Number of pillars = 14

» Shape of solid that is pillar = Cylinder

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~ For the Volume of each pillar ::

We know that,

\;\sf{\rightarrow\;\;Volume\;of\;Cylinder\;=\;\bf{\pi r^{2}h}}→VolumeofCylinder=πr

2

h

By applying values, we get

\;\sf{\rightarrow\;\;Volume\;of\;Pillar\;=\;\bf{\pi\:\times\:(20)^{2}\:\times\:10}}→VolumeofPillar=π×(20)

2

×10

\;\sf{\rightarrow\;\;Volume\;of\;Pillar\;=\;\bf{\pi\:\times\:20\:\times\:20\:\times\:10}}→VolumeofPillar=π×20×20×10

\;\sf{\rightarrow\;\;Volume\;of\;Pillar\;=\;\bf{\pi\:\times\:400\:\times\:10}}→VolumeofPillar=π×400×10

\;\sf{\rightarrow\;\;Volume\;of\;Pillar\;=\;\bf{\pi\:\times\:4000}}→VolumeofPillar=π×4000

\;\sf{\rightarrow\;\;Volume\;of\;Pillar\;=\;\bf{\red{4000\pi\;\:cm^{3}}}}→VolumeofPillar=4000πcm

3

This is the Volume of Concrete used in on Pillar.

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~ For amount of concrete used in 14 pillars ::

We already got the value of volume of one pillar. So, volume of 14 pillars will be

✒ Volume of 14 such pillars = 14 × Volume of one pillar

\;\bf{\Longrightarrow\;\;Volume\;of\;14\;pillars\;=\;14\:\times\;4000\pi}⟹Volumeof14pillars=14×4000π

By applying the value of π as 22/7 , we get

\;\bf{\Longrightarrow\;\;Volume\;of\;14\;pillars\;=\;14\:\times\;4000\:\times\:\dfrac{22}{7}}⟹Volumeof14pillars=14×4000×

7

22

\;\bf{\Longrightarrow\;\;Volume\;of\;14\;pillars\;=\;2\:\times\;4000\:\times\:22}⟹Volumeof14pillars=2×4000×22

\;\bf{\Longrightarrow\;\;Volume\;of\;14\;pillars\;=\;176000\;\;cm^{2}}⟹Volumeof14pillars=176000cm

2

Thus this the required answer, which shows the amount of concrete in 14 pillars.

\;\underline{\boxed{\tt{Total\;\:Amount\;\:of\;\:concrete\;\:mixture\;=\;\bf{\purple{176000\;\;cm^{2}}}}}}

TotalAmountofconcretemixture=176000cm

2

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★ More to know :-

\;\tt{\leadsto\;\;TSA\;of\;Cylinder\;=\;2\pi rH\;+\;\pi r^{2}}⇝TSAofCylinder=2πrH+πr

2