Question

The pillars of of a temple are cylindrically shaped . if each pillar has a circular ba se of radius 280cm and height 10m , how much concrete mixture would be required to build 14 such pillars

Answer 1

$\huge\bigstar\underline\mathfrak\red{Answer}$

$\large\texbf\boxed{volume\:of\:concrete\:in\:14\:cylindrical\:pillar\:=\:3449.6\:cubic\:metre}$

_________________________

$\huge\bigstar\underline\mathfrak\red{Explanation}$

Given :

Height of cylinder (h) = 10 m

Radius (r) = 280 cm = 2.8 m

To find :

• Concrete mixture would be required to build 14 such pillars.

Solution :

We know that, the pillar is cylindrical shaped, so we use the formula of volume of cylinder.

Therefore,

Volume of concrete in one cylindrical pillar = πr²h

Put the given values in above formula,

= 22/7 × 2.8 × 2.8 × 10

= 246.4 m³

Therefore, volume of concrete in one cylindrical pillar = 246.4 m³

________________________

Now,

Volume of concrete in 14 cylindrical pillars = 246.4 × 14

= 3449.6 m³ [ required answer ]

Answer 2

Answer :

Volume of concrete in 14 cylindrically pillars - 3449.6 m³

Explanation :

Given :

Shape of pillars of of a temple - Cylindrically shaped.

Each Pillar has a circular base of radius - 280cm.

Each Pillar has a height - 10m.

To Find :

Concrete mixture would be required to build 14 such pillars.

Solution :

As given,

Height - 10m.

Radius - 280cm.

We know that :

Volume of concrete in 1 pillars Cylindrically shaped :

${\bigstar\color{aqua}{\boxed{\sf \pi\;r^2\;h}}}$

Values in Equation,

$\sf \\ \\ \implies \dfrac{22}{7}\times 2.8 \times 2.8 \times 10\\ \\ \\\implies 246.4 m^3$

Hence,

Volume of concrete in 1 pillars Cylindrically shaped - $\246.4 m^3$

Now, Simply multiply $246.4 m^3$ with 14.

So,

⇒ 246.4 × 14

⇒ 3449.6 m³

∴ Volume of concrete in 14 cylindrically pillars - 3449.6 m³.