Question

The pilot of a helicopter at an altitude of 1200 m finds that two ships are approaching it in the same
direction on the same side of the helicopter. The angles of depression of the ships from the helicop-
ter are 60° and 45° respectively. Find the distanc between the two ships. (Take 3 = 1.73)
3​

Answer 1

Answer:  

508 metres  

Step-by-step explanation:  

let AB be the height at which the pilot is flying  

AB=1200 m  

From the information, we construct a diagram as given  

here,

x=distance between ships  

Now,in triangle ABC  

tan60°=AB÷BC  

root (3)=1200÷y  

y=1200÷root (3)

y=400×root (3)

In triangle ABD  

tan45°=AB÷BD  

1=1200÷x+y

x+y=1200  

x=1200-y  

(we have y=400×root (3))  

x=1200-400×root (3)  

(we know that root (3)=1.73)  

x=1200-400×1.73

x=1200-692

x=508 metres

Therefore, the distance between ships is 508 metres

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Answer 2

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