Question

The pipe has length 26 cm , internal diameter 5 cm and thickness 0.5

Answer 1

Answer:

This is the method for this question

Answer 2

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Given,

$\sf{Length \: of \: pipe = 26 \: cm}$

$\sf{Internal \: diameter= 5 cm}$

$\sf{Then, Internal \: radius = 2.5 cm}$

$\sf{And, Thickness = 0.5 cm}$

$\sf{Outer \: radius= 2.5+0.5 = 3 cm}$

$\sf{Volume \: of \: pipe = \pi {R}^{2} h - \pi {r}^{2} h}$

$\sf{Volume \: of \: pipe = \frac{22}{7} ( {3}^{2} )(26) - \frac{22}{7}( {2.5}^{2} )(26)}$

$\sf{Volume \: of \: pipe = 224.7{cm}^{3} }$