The pistons of a hydraulic lift have areas of 3.0 cm and 12.2 cm2. A force exerted on the smaller piston lifts a maximum load of 475 N. What force is required to lift this load?
Answers
Answered by
0
Answer:
use formula =
force2 = area 2/area 1. × force 1.
MARK ME AS BRAINLIST✌✌FOLLOW ME⚠️⚠️MARK ME AS BRAINLIST✌✌FOLLOW ME⚠️⚠️
Similar questions