The pitch of a screw gauge is 0.5 mm and there are 50 divisions on circular scale. When there is nothing between the two studs of screw gauge, 46th division of circular scale is coinciding with reference line and zero of main scale is not visible. When a wire is placed between the studs, the linear scale reads 2 divisions and 20th division of circular scale coincides with the reference line. The correct statement is/are :
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The pitch of a screw gauge is 0.5mm and there are 50 divisions on the circular scale. In measuring the thickness of a metal plate, there are five divisions on the pitch scale (or main scale) and thirty fourth divisions coincide with the reference line. Calculate the thickness of the metal plate. = 2.84mm.
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