Question

The pitch of a screw gauge is 0.5mm and its head scale has 50 divisions. The least count of the screw gauge is​

Answer 1

Answer:

The pitch of the screw gauge = 0.5 mm.

There are 50 divisions in the head scale.

The least count is = Pitch/Number of divisions

⇒ LC = 0.5/50

⇒ LC = 0.01 mm

Hence, the least count of the screw gauge is 0.01 cm.

➸ What is a screw gauge ?

It is an instrument to measure the diameter of a substance, such as a thik wire.

Thw following are the parts of a screw gauge :

(Refer the attachment)

• Stud
• Screw
• Frame
• Pitch scale
• Circular scale
• Thimble
• Ratchet

The pitch of the screw gauge can be calculated by : Distance moved by screw/Number of rotations.

The least count can be calculated : Pitch/Number of divisions.

Answer 2

Answer:

0.01 mm

Explanation:

Given that, the pitch of a screw gauge is 0.5mm and its head scale has 50 divisions.

We have to find the least count of the screw gauge.

We know that,

Least count = (Pitch of a screw gauge)/(Number of divisions on head scale)

From above data we have pitch of a screw gauge is 0.5 mm and number of divisions on a head scale is 50.

Substitute the values in the above mentioned formula,

→ Least count = 0.5/50

→ Least count = 0.1/10

On solving we get,

→ Least count = 0.01

Hence, the least count of the screw gauge is 0.01 mm.