The pitch of a screw gauge is 1 mm and there are 100 division on the circular head. While measuring the diameter of a wire, the main scale reads 3 mm and 55th division is in line with the base line. The area of the cross section of wire is
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Correct option is
D
5.22 mm
The least count of the screw gauge LC= pitch/ total number of circular divisions =1/100=0.01 mm.
The final reading or diameter of the wire D=MSR+(CSR×LC)=5+(25×0.01)=5.25 mm
As the screw gauge has positive zero error so the zero error will be subtracted from final result.
Thus, the correct vale of diameter =5.25−0.03=5.22 mm
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