The pitch of a screw gauge is 1mm find its circular scale division, if least count is 0.001cm
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Answer:
L.C. of the screw gauge =
Numberofdivisionsoncircularscale
Pitch
=
100
1
=0.01mm
Given : Main scale reading =1 mm
Circular scale reading =0.01×47=0.47
∴ Diameter of wire = Total reading =1.47mm=0.147cm
Curved surface area = π×dl=π×(0.147)(5.6)=2.586≈2.6cm
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