The pitch of a screw gauge is I mm and there
are 100 divisions on the circular scale. While
measuring the diameter of a wire, the linear scale
reads 1 mm and 47th division on circular scale
coincides with the reference line. The length of
the wire is 5.6 cm. Find the curved surface area
(in cm) of the wire in proper significant figures. (((
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Answer:
Least count = \frac{1mm}{100}=.01mm
Diameter = M. S. +( No. of division coinciding with main scale × Least count.)
= 1 mm + 47 × 0.01 mm
= 1.47 mm = 0.147 cm.
Curved surface area = πdL = \frac{22}{7} *1.47*5.6 = 2.6 cm^{2}
Explanation:
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