Question

The pitch of the screw gauge is 0.5 mm. Its circular scale contains 50 divisions. The least count of the screw gauge is(a) 0.001 mm (b) 0.01 mm(c) 0.02 mm (d) 0.025 mm

Answer 1

Least count of the screw gauge =pitch/no. of divisions on the head scale

=0.5/50=1/100

=0.01mm

Therefore ans:(b)0.01mm

Answer 2

The least count of the screw gauge is 0.01 mm. (Option b)

Given,

The pitch of the screw gauge = 0.5 mm

Number of divisions = 50 divisions

To Find,

The least count of the screw gauge

Solution,

An accuracy screw gauge facilitates the measurement of thin wire diameters, radiuses, or thicknesses and allows measuring the diameter and thickness of thin metal sheets.

The least count of a screw gauge is given by the division of its pitch by the number of divisions on its circular scale.

Least count = $\frac{Pitch}{Number of divisions}$

Least count = $\frac{0.5 mm}{50}$

Least count = 0.01 mm

Hence, we get the least count as 0.01 mm.

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