The pitch of the whistle of an engine appears to rise to 1.2 times the original value when it approaches a stationary observer calculate the speed of the engine
Answers
Answered by
21
Hey dear,
◆ Answer-
v' = 56.67 m/s
◆ Explaination-
As pitch of the whistle depends on apparent frequency.
f' = 1.2 f
Let v' be speed of engine.
According to Doppler effect in sound,
f' = f (v / v-v')
1.2 f = f (340 / 340-v')
408 - 1.2v' = 340
1.2v' = 68
v' = 56.67 m/s
Therefore, speed of the engine is 56.67 m/s.
Hope it helps...
◆ Answer-
v' = 56.67 m/s
◆ Explaination-
As pitch of the whistle depends on apparent frequency.
f' = 1.2 f
Let v' be speed of engine.
According to Doppler effect in sound,
f' = f (v / v-v')
1.2 f = f (340 / 340-v')
408 - 1.2v' = 340
1.2v' = 68
v' = 56.67 m/s
Therefore, speed of the engine is 56.67 m/s.
Hope it helps...
Answered by
0
Answer:
55 m/s
Explanation:
and should be 55m/s
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