Math, asked by mejiamartinezbanessa, 13 hours ago

The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table? Use 3.14 for pi.

Answers

Answered by shahkhushi343
1

Answer:

don't know the answer

Step-by-step explanation:

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Answered by pradiptadas2007
3

Answer:

The minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table is 10 in.

Step-by-step explanation:

Area of the pizza = 78.5 in²

(∵area of a circle = πr²)

So, 78.5 = πr²

⇒78.5 = 3.14 × r²

⇒r² = 78.5 × 1/3.14

⇒r² = 25

⇒r = √25 = 5

Hence, radius of the pizza is 5 in.

Minimum width of placemat = Diameter of the pizza

Therefore, diameter = (5+5) in = 10 in.

∴Width of placemat needed is 10 in.

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