The pka of a weak acid (HA) is4. 5.the pOH of an aqueous buffer solution of HA in which 50:of acid is ionized
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ph =pka=4.5 ; this is because the ratio log [A^-]/[HA]=log o.5/0.5=0
hence, ph=pka in the formulla ph=pka+log [A^-]/[HA]
hence, poh= 14-ph=14-4.5=9.5
Explanation:
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