Question

The plane of a rectangular coil makes an angle of 60deg with a direction of a uniform mag.field between the poles of 4×10^-2T. The coil is of 20turns, measuring 20cm by 100cm and carries a current of 0.5A, calculate the torque acting on the coil.

Answer 1

$\textbf{\underline{\underline{Solution:-}}}$

Given:

Angle with magnetic filed (θ) = 60°

Strength (B) = 4×10^-2 T

No. of turns (N) = 20

Lengh = 20 cm= 0.2 m and breadth = 100cm= 1m

So, Area of coil = 0.2 × 1 = 0.2 m^2

Current (I) = 0.5A

Now,

Torque on a coil (T) = BINA cosθ

= 4 ×10^-2 ×0.5×20 × 0.2 cosθ

= 4 × 10^-3 Nm

So, T = 4 × 10^-3 Nm

Thank you ☺

@Swigy

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Answer 2

Solution is given in the picture.

Please look at the picture.