Question

The plane starting from rest acceleration at 3m/s^2 for 25s.calculate the increase in velocity :
a)1s
b)5s
c)25s​

Answer 1

Given:-

• Initial Velocity of Plane = 0m/s

• Acceleration of Plane = 3m/s²

• Time Taken = 25s.

To Find:-

• The Increase in Velocity i.e, Final Velocity.

Formulae used:-

• v = u + at

where,

v = Final Velocity

u = Initial Velocity

a = Accceleration

t = Time

Now,

v = u + at

v = 0 + 3 × 25

v = 75m/s

Hence, The Increase in Velocity is 75m/s

EXTRA INFORMATION.

• Velocity is defined as Displacement covered by body in Per unit time

• Velocity is a vector Quantity.

• The Rate of the Change in Velocity is known Acceleration.

• Acceleration is a Vector Quantity

Answer 2

$\rm{ \orange{\bigstar Given \longrightarrow }}$

• initial velocity [v]= 0m/s

• acceleration [a] = 3m/s²

• Time [t] = 25s

       

$\rm{ \blue{\bigstar Find \longrightarrow }}$

Final velocity [v]

         

$\rm{ \red{\bigstar Formula \ used \longrightarrow }}$

$\boxed{\tt{v=u+at}}$

where,

v= final velocity,

u= initial velocity,

a= acceleration

t= time

     

$\rm{ \pink{\bigstar SoLution \longrightarrow }}$

By using newton first equation,

$\sf{v=u+at}$

Put the given values in the formula , we get

$\sf{v= 0+ 3\times 25}$

$\sf{v= 75}$

$\bf{\underline{\small{\therefore Increase\ in\ velocity\ of\ plane\ is\ 75m/s.}}}$

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