Question

The plane through the Intersection of the planes
q+y+z=1 and 24 +34-2 +420 and parallel to y-axis also
passes through the point: :​

Answer 1

Answer:

Equation of plane

(x+y+z−1)+λ(2x+3y−z+4)=0

⇒(1+2λ)x+(1+3λ)y+(1−λ)z−1+4λ=0

dr's of normal of the plane are

1+2λ,1+3λ,1−λ

Since plane is parallel to y-axis,

1+3λ=0

⇒λ=

3

−1

So the equation of plane is

x+4z−y=0

Point (3,2,1) satisfies this equation

Hence Answer is (3).