Physics, asked by anj21, 1 year ago

The plates A and B of a parallel plate capacitor have a potential difference of 15V. A proton (m= 1.67❌10^-27kg) is moved from the positive plate A and B. calculate the speed of the proton near plate B.

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Answered by Anonymous

14

use formula eV = 1/2mv^2 (all quantities you have mentioned)

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