Question

The plates of a parallel plate capacitor are 5mm apart and 2m^2 in area , the plates are in vaccum, a potential difference of 1000 v is applied across the capacitor calculate the charge on each plate and electric intensity in the space between the two points ​

Answer 1

Answer:

Area(A)=2m^2

Area(A)=2m^2distance between the capacitor (d)=5mm=5×10^-3

Area(A)=2m^2distance between the capacitor (d)=5mm=5×10^-3V=1000V

Area(A)=2m^2distance between the capacitor (d)=5mm=5×10^-3V=1000VNow ,

Area(A)=2m^2distance between the capacitor (d)=5mm=5×10^-3V=1000VNow ,using the formula,

Area(A)=2m^2distance between the capacitor (d)=5mm=5×10^-3V=1000VNow ,using the formula,C=€°A/d

Area(A)=2m^2distance between the capacitor (d)=5mm=5×10^-3V=1000VNow ,using the formula,C=€°A/d=8.845×10^-12×2÷(5×10^-3)

Area(A)=2m^2distance between the capacitor (d)=5mm=5×10^-3V=1000VNow ,using the formula,C=€°A/d=8.845×10^-12×2÷(5×10^-3)=3.538×10^-9

Explanation:

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