Question

The plates of a parallel plate capacitor are charged upto 100V and disconnected from the source. A 2mm thick plate is inserted between the plates, then to maintain the same potential difference, the distance between the capacitor plates is increased by 1.6mm. The dielectric constant of the plate is :

Answer 1

Answer:

As battery is disconnected, so charge will remain the same.

It is given that final potential is the same.

So final capacitance should be C

1

=C

2

d

ε

0

A

=

(1.6+d)−t(1−1/K)

ε

0

A

⇒K=5

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