Question

The plates of a parallel plate capacitor are separated by d cm. a plate of thickness r cm with dielectric constant k1 is inserted and the remaining space is filled with a plate of dielectric constantk2 . if q is the charge on the capacitor and area of plates is acm2 each, then potential difference between the plates is

Answer 1

0 the potential difference

Answer 2

Answer:

It is used by potential difference formula ::V=Ed=Qd/Ae(epsilon_0)

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