Question

The plates of a parallel plate capacitor have an area of 90 cm² each and are separated by 2.5 mm. The capacitor is charged by a 400 volt supply. How much electrostatic energy is stored by the capacitor?(a) 2.55 × 10⁻⁶ J(b) 1.55 × 10⁻⁶ J(c) 8.15 × 10⁻⁶ J(d) 5.5 × 10⁻⁶ J

Answer 1

Answer:

Explanation:

Cross section area of parallel plate capacitor , A = 90 cm² = 90 × 10^-4 m²

separation between plates , d = 2.5mm = 2.5 × 10^-3 m

C = CoA/d

C = (8.85 × 10^-12 × 90 × 10^-4)/(2.5 × 10^-3)

= 32 × 10^-12 F = 32pF

The electrostatic energy stored by the capacitor , U = 1/2 CV²

U = 1/2 × 32 × 10^-12 × (400)²

= 1/2 × 32 × 10^-12 × 160000

= 16 × 10^-12 × 16 × 10^4

= 256 × 10^-8 = 2.56 × 10^-6 J

The volume , V = A × d = 90 × 10^-4 × 2.5 × 10^-3

= 2.25 × 10^-5 m³

Thus, energy per unit volume = Energy/volume

= (2.56 × 10^-6)/(2.25 × 10^-5) J/m³

= 1.13 × 10^-1

= 0.113 J/m³

Answer 2

Hey Mate!

✓✓ Your Answer ✓✓

################

Good Question

**********************

Option :↓Choosen below↓

_____________________

The plates of a parallel plate capacitor have an area of 90 cm² each and are separated by 2.5 mm. The capacitor is charged by a 400 volt supply. How much electrostatic energy is stored by the capacitor?

(a) 2.55 × 10⁻⁶ J

.........