Question

The player kicks a 0.5kg football and gives with a velocity of 10m/s starting from the rest . The constant between the force and ball last for 1/50 sec . what is the force of impact​

Answer 1

Answer:

$\frak{\pink{Given}}\begin{cases} \sf{\green{Mass=0.5 \: kg}}\\ \sf{\blue{Final \: Velocity =10 \: m/s}}\\ \sf{\orange{Initial \: Velocity=0 \:m/s }}\\ \sf{\red{Time= \dfrac{1}{50} = 0.02 \: seconds}}\end{cases}$

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Solution :

$: \implies \sf Acceleration = \dfrac{Change \: in \: velocity}{Time \: taken}$

$:\implies\sf Acceleration = \dfrac{Final \: velocity - Initial \: velocity}{Time \: taken}$

$:\implies\sf Acceleration = \dfrac{10 - 0}{0.02}$

$:\implies \underline{ \boxed{\frak{ Acceleration = 500 \: m/s^{2}} }}$

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☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$\dashrightarrow\:\:\sf Force = Mass \times Acceleration$

$\dashrightarrow\:\:\sf Force =0.5 \times 500$

$\dashrightarrow\:\:\underline{\boxed{\frak{ Force = 250 \: Newtons}}}$

Answer 2

Given :

• Mass (m) = 0.5 kg
• Final Velocity (v) = 10 m/s
• Initial Velocity (u) = 0 m/s
• Time (t) = 1/50 = 0.02 seconds

To find :

• The force impact

According to the question,

Now according to newtons first equation of motion we will calculate acceleration,

$\mapsto{ \boxed {\sf \green{v = u + at}}} \\ \\ \mapsto \sf{10 = 0 + a \times 0.02} \\ \\ \sf \mapsto{10 - 0 = 0.02a} \\ \\\mapsto\sf{10 \: \: \: \: = \: \:0.02a} \\ \\ \mapsto \sf{ 10 \times 0.02 = a } \\ \\ \mapsto \sf{500 \: {ms}^{2} = a} \red \bigstar$

So,the acceleration is 500 m/s²..

Now we will find the force,

$\mapsto\boxed{ \sf \green{Force (F)= Mass (m) \times Acceleration(a)}} \\ \\ \mapsto \sf{0.5 \times 500} \\ \\ \mapsto \sf{ \frac{5}{1 \cancel0} \times 50 \cancel0 } \\ \\ \sf \mapsto{250 \: N} \red \bigstar$

So,the force is 250 N..