Math, asked by 0x0, 2 months ago

The player loses on the first roll if they roll a sum of 2, 3, or 12. What is the probability of losing on the first roll?

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Answered by avann84

Answer:

hiii weeb!!!

Step-by-step explanation:

If the sum is 2, 3, or 12, he/she loses. If the sum is anything else, then he/she continues throwing until that number appears again, or throws a 7, where the game ends in a loss. What I do know is that P(7)=6/36, P(11)=2/36. So P(winning) in first roll is 8/36.

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