Question

The playground of a school has an area of 220 sq.m and its length is 19.2 m. If the length of the playground is increased to 21.6 m while keeping its breadth constant, what will be the new area of the playground?​

Answer 1

Answer:

247.5sq.m

Step-by-step explanation:

Area = Length x Breadth

let the area of playground will be A1 and length will be L1

and the area of new playground will be A2 and length will be L2 while keeping its breadth constant.

Area = L x B

A1/A2 = L1/L2

220/A2 = 19.2/21.6

220 x 21.6 = 19.2 x A2

A2 = 4752/19.2

A2 = 247.5sq.m