the pocket money of joan and joce are in the ratio 10:8 if joan had ₹20more than joyee find the pocket money of each
anitamanderwal1:
joan - 100.. joce-80
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Take Joan’s pocket money as x
Joyce’s pocket money =8x
Joan’s pocket money= 20+8x
20+8x:8x = 10:8
Then cross multiply,
(20+8x)8= 160+64x
(8x)10= 80x
160+64x = 80x
64x+160=80x
64x-80x= -160
(64-80)x = -16x
-16x= -160
x= -160/-16 = 10
Therefore, x=10
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Joyce’s pocket money =8x
Joan’s pocket money= 20+8x
20+8x:8x = 10:8
Then cross multiply,
(20+8x)8= 160+64x
(8x)10= 80x
160+64x = 80x
64x+160=80x
64x-80x= -160
(64-80)x = -16x
-16x= -160
x= -160/-16 = 10
Therefore, x=10
Hope it was helpful!!
If it was helpful please mark my answer as the brainliest
Answered by
2
this is the ans joce - 80 nd joan - 100
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