The point (0,-1),(2,1),(0,3) and (-2,1) are the vertices of
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parallelogram is answer
teja2457:
with solution
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formula used : d = √(x₁ - x₂)² + (y₁ - y₂)²
A(0,-1) B(2,1) C(0,3) D(-2,1)
AB = √(0-2)² + (-1-1)²
= 2√2 units
BC = √(2-0) + (1-3)²
= 2√2 units
CD = √(0+2)² + (3-1)²
= 2√2 units
AD = √(0+2)² + (-1-1)²
= 2√2 units
and the diagonals
AC = √(0-0)² + (-1-3)²
= √16 = 4 units
BD = √(2+2)² + (1-1)²
= √16 = 4 units
Hence the points are the vertices of a square,
☆ Criteria for square ::
☆ All sides are equal.
☆ Diagonals are equal.
WISH IT HELPS YOU !!
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