The point (1,2) lies on y=2x+c
, then the value of c is
a) I b) - 1 c)2 d)0
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MATHS
The points (1,3) & (5,1) are two opposite vertices of a rectangle. The other two vertices lie on the line y=2x+c. Find c & the remaining vertices
November 22, 2019avatar
Chandrakant Guna
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Since, diagonals of rectangle bisect each other, so mid point of (1,3) and (5,1) must satisfy y=2x+c i.e (3,2) lies on it
⇒2=6+c⇒c=−4
Therefore other two vertices lies on y=2x−4
Let the coordinate of B be (x,2x−4)
Therefore slope of AB . slope of BC=−1
⇒(
x−1
2x−4−3
).(
x−5
2x−4−1
)=−1
⇒(x
2
−6x+8)=0⇒x=4,2⇒y=4,0
Hence, required points are (4,4),(2,0)
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