The point (2k-8,10) lies on the y axis find k
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Answered by
3
the line lies on y axis so y = 0
2k-8=0
2k=8
k=8/2
k=4
2k-8=0
2k=8
k=8/2
k=4
shifa200499:
Thanks
Answered by
4
if the points lie on y axis then the X co-ordinate will be zero.
2k-8=0
2k=8
k=4
2k-8=0
2k=8
k=4
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