The point (3,-4) is the center of the circle of AB is the diameter of the circle and B is (5,-6) find the coordinates of A
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suppose point p is centre of circle
having a coordinates (3,-4)(x,y)
suppose the coordinates of A is(X1,y1) and the coordinates of point B is( X2,y2)
by midpoint formula
x = X1+ X2/2
3=X1 + 5/2
3×2 = X1 + 5
6=X1 + 5
X1 = 5 - 6
X1 = -1
y = y1 + y2 / 2
-4 = y1 + -6 /2
-8 = y1 + -6
y1 = -6 + 8
y1 = 2
the coordinates of point A is ( -1,2 )
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