Question

The point (4,4) is in the locus whose equation is y^2=ax .show that (16,8)is another point on the locus ​

Answer 1

Step-by-step explanation:

Given : point (4,4) is in the locus

equation y²=ax

(4)² = a*(4)

a= 16/4 = 4

We have to check that point (16,8) is also point on the locus .

so, it should be y²= ax => y²=4x

So putting value :- (8)² = 4*(16)

64 = 64

Since LHS = RHS is equal we can say that (16,8) is on the locus .

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