the point (-5,1), (1,p) & (4,-2) are collinear if the value of p is
Ans:
1/2 | -5(p-(-2)) + 1(-2-1) +4(1-p)|=0
1/2 | -5(p+2) -3+4-4p|=0
1/2 |-5p+10-3+4-4p|=0
1/2 | -5p-9-4p|=0
1/2 |-5p-4p-9|=0
-9p-9=0
-9p-9=0
-9p-9
-9p=9
p=9/9
. p=1
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