the point 7,2 and - 1,0 lie on a line
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Question:
The points (7, 2) and (- 1, 0) lie on a line
(1) 7y = 3x - 7 (2) 4y = x + 1
(3) y = 7x + 7 (4) x = 4y + 1
Solution:
The given points are (7, 2) and (- 1, 0).
Then the slope of the straight line passing through these points is
m = (0 - 2) / (- 1 - 7) = (- 2)/(- 8) = 1/4
∴ the equation of the required straight line is
(y - 0) = 1/4 * {x - (- 1)}
or, y = 1/4 * (x + 1)
or, 4y = x + 1
∴ option (2). 4y = x + 1 is correct.
Rule:
The equation of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is given by
y - y₁ = m (x - x₁)
where m = slope of the line = (y₂ - y₁)/(x₂ - x₁)
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