Math, asked by pavansurwase125, 1 year ago

The point A(1-2) B(2,3) C(K,2) and d (-4,-3) ar the vortices of a parallogram find the value of k

Answers

Answered by Tusharnischal13
3

Answer:


Step-by-step explanation:

Abcd is a parallelogram

Diagonals of parallelogram bisect each other

Coordinates of mid point of ac =Coordinates of mid point of bd

(1+k/2, - 2+2/2)=(2-4/2, 3-3/2)

1+k/2,0 = - 1,0

On comparing,

K=-3

Answered by basilvictor
3

Answer:

K = 2.3245

or, K = -10.3245

Step-by-step explanation:

Opposite sides of a parallelogram are equal.

Therefore,

AB = √((2 - 1)² + (3-(-5)²) = √(1 + 64) = √65

CD = √((K-(-4))² + (2-(-3))²) = √(K² + 16 + 8K + 25)

AB = CD

=> √(K² + 16 + 8K + 25) = √65

Squaring both sides

=> K² + 8K + 41 = 65

=> K² + 8K - 24 = 0

Applying shridhar acharya formula

K = (-b ± √(b² - 4ac))/2a

Where, a=1 b=8 c=-24

K = 2.3245

or, K = -10.3245

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