the point A(-1, 2), B(x, y) and C = (4, 5) are such that BA = BC
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BA=BC
therefore
B is the midpoint of AC
midpoint of A(-1,2)=(x1,y1) and C(4,5)=(x2,y2) is B
(x,y)= (x1+x2/2,y1+y2/2)
=(-1+4/2,2+5/2)
B(x,y)=(3/2,7/2)
therefore
B is the midpoint of AC
midpoint of A(-1,2)=(x1,y1) and C(4,5)=(x2,y2) is B
(x,y)= (x1+x2/2,y1+y2/2)
=(-1+4/2,2+5/2)
B(x,y)=(3/2,7/2)
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