Question

the point (a,1) lies on the graph of equation x+3y=7 then find a​

Answer 1

Answer:

a=4

Step-by-step explanation:

Hope it's helps you...

Answer 2

Answer:

a = 4

Note:

• If a point lies on the graph of any equation , then the coordinates of that point must satisfy the given equation.

• If the coordinates of any point satisfy the given equation , then that point lies on the graph of the equation.

Solution:

Here,

The given equation is :

x + 3y = 7 ---------(1)

Also,

It is said that , the point (a,1) lies on the graph of the given equation.

Thus,

The coordinates of the point (a,1) must satisfy the given equation.

Now,

Let's put it coordinates of point (a,1) in the given equation to find the value of a .

Thus,

Putting x = a and y = 1 in eq-(1) ,

We get ;

=> x + 3y = 7

=> a + 3×1 = 7 { (a,1) => x = a , y = 1 }

=> a + 3 = 7

=> a = 7 - 3

=> a = 4

Hence,

The required value of a is 4 .