the point A(3,0) B ( a,-2) and C (4,-1) are the vertices of triangle ABC and right angled at vertex A. find the value of a
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Step-by-step explanation:
Step1:using Pythagoras theorem
AB²+BC²=AC²
Step2:we know value of a present at X coordinate.so,
(a-3)²+(4-a)²=(4-3)²
2(a²-7a+12)=0
a²-4a-3a+12=0
a(a-4)-3(a-4)=0
a=4 or 3.
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