Question

The point A (3, y) is equidistant from the points P (6, 5) and Q (0, -3).
Find the value of y.

Answer 1

Answer:

Step-by-step explanation:

Let X be a random element in a metric space (ℱ,d), and let Y be a random variable with value 0 or 1. Y is called the class, or the label, of X. Let (X i ,Y i ) 1≤i≤n be an observed i.i.d. sample having the same law as (X,Y). The problem of classification is to predict the label of a new random element X. The k-nearest neighbor classifier is the simple following rule: look at the k nearest neighbors of X in the trial sample and choose 0 or 1 for its label according to the majority vote. When (ℱ,d)=(ℝ d ,||·||), C. J. Stone [Ann. Stat. 5, 595–645 (1977; Zbl 0366.62051)] proved the universal consistency of this classifier: its probability of error converges to the Bayes error, whatever the distribution of (X,Y). We show in this paper that this result is no longer valid in general metric spaces. However, if (ℱ,d) is separable and if some regularity condition is assumed, then the k-nearest neighbor classifier is weakly consistent.