the point A (3,y) is equidistant from the points P(6,5) and Q(0,-3). find the value of y.
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(6-3)²+(5-y)²=(3-0)²+(y+3)²,
3²+(5²+y²-10y)=3²+(y²+3²+6y),
9+25+y²-10y=9+y²+9+6y,
25-9=6y+10y,
16=16y,
then
16/16 = y,
y=1
3²+(5²+y²-10y)=3²+(y²+3²+6y),
9+25+y²-10y=9+y²+9+6y,
25-9=6y+10y,
16=16y,
then
16/16 = y,
y=1
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