The point A (a,b) and point B (b,0) lie on Y= 8 x +3.
(I) find the value of a and b
(ii) Is (2,0) solution of above equation .
(iii) find other two solution ofc above equation.
Answers
Answer:
(i)Since (a,b) and (b,0) lie on the line y=8x+3 , they must satisfy this equtaion .
→b=8a+3
→0=8b+3
Solving we get b=
8
−3
and a=
64
−27
(ii)Since (2,0) doesn't satisy y=8x+3 ,therefore it is not its solution .
Step-by-step explanation:
Given :-
The point A (a,b) and point B (b,0) lie on Y= 8 x +3.
To find :-
I) find the value of a and b ?
(ii) Is (2,0) solution of above equation ?
(iii) find other two solution ofc above equation ?
Solution :-
Given equation is Y = 8X+3 ------(1)
1) Finding a and b values :-
If A(a,b) lies on the given equation then it satisfies the given equation.
Put X = a and Y = b in (1)
=> b = 8a + 3 ---------(2)
and
If B(b,0) lies on the given equation then it satisfies the given equation.
Put X = b and Y = 0 in (1) then
=> 0 = 8b + 3
=> 8b = -3
=> b = -3/8
On Substituting the value of b in (2) then
=> -3/8 = 8a +3
=> (-3/8)-3 = 8a
=> (-3-24)/8 = 8a
=> -27/8 = 8a
=>8a = -27/8
=> a = (-27/8)×(1/8)
=> a = -27/64
The value of a = -27/64 and b = -3/8
2) Checking for (2,0) :-
Given point = (2,0)
If (2,0) lies on the given equation then it satisfies the given equation.
Put X = 2 and Y = 0 in (1)
LHS = Y = 0
=> RHS = 8(2)+3
=> 16+3
=> RHS = 19
LHS ≠ RHS
So ,(2,0) is not a solution of the given equation.
3) Finding other 2 solutions :-
Given equation is Y = 8X+3 ------(1)
Put X = 0 then
=> Y = 8(0)+3
=> Y = 0+3
=> Y = 3
The solution = (0,3)
Put Y = 0 then
=> 0 = 8X+3
=> 8X = -3
=> X = -3/8
The solution = (-3/8,0)
Answer :-
1)The value of a = -27/64 and b = -3/8
2)(2,0) is not a solution of the given equation.
3) The other two solutions are (0,3) and (-3/8,0)
Used formulae:-
- If a number is a solution of the given equation then it satisfies the given equation . i.e.If we Substituting the values in it for the variables then LHS = RHS.