The point A is (0, 7), and the point B is (6, 9).
Find the gradient of AB.
(b)The equation of the line AB is x + Py + Q = 0
Find P and Q.
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Answer:
So P=-3 and Q=7/3
Step-by-step explanation:
The point A is (0, 7), and the point B is (6, 9).
Gradient=(9-7)/(6-0)
m=2/6=1/3
(b) The line x+Py+Q=0
y=-x/P-Q/P
this eqn is in the form
y=mx+C
so gradient m=-1/P=1/3
so p=-3
it passes through (0,7)
so 7P+Q=0
Q=-7/P
Q=-7/-3=7/3
So P=-3 and Q=7/3
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