Question

the point at which the graph of a linear equation(- X+y=10) cuts the y-axis is give ans fastly​

Answer 1

☞︎︎︎To cut the x-axis,y coordinate has to be(0)zero

$- x + 0 = - 1 0 \\ - x = - 10 \\ x = 10$

➪so the point of intersection at the x.axis will be (10,0)

➪To cut the y-axis,x coordinate has to be (0)zero.

$0 + x = - 10 \\ y = - 10 \\ y = - 10$

☞︎︎︎so the point of intersection at the y axis will be(0,-10)