Question

the point at which y=2x-1 cuts the x-axis is​

Answer 1

Answer:

The equation y=x

2

−x−12 cuts x axis at y=0

put y=0, we get x

2

−x−12=0

x

2

−x−12=0

x

2

−4x+3x−12=0

x(x−4)+3(x−4)=0

(x−4)(x+3)=0

x=4 or x=−3

The points cut x axis are (4,0) and (−3,0)

we put x=0 , when it cuts y axis

y=0

2

−0−12

y=−12

Therefore, the required point is (0,−12)

Answer 2

We have, y=2x-1,

Then, y+1=2x

put y=0, then x = 1/2

Hence the points are (1/2,0) where the line cuts the x-axis.

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