The point b,3 lie on the graph of the linear equation 2x-3y+11. Find 'b'
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Answered by
2
Answer:
hey mate
2x-3y+11=0 (where x=b , y=3)
2×b -3×3+11=0
2b -9+11=0
2b+2=0
2b = -2
b = -2/2
b= -1
hope it will help you
Answered by
1
Answer:
bro it is easy try it u will get infinte values
Step-by-step explanation:
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